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# Height of Rotterdam Tower

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Derelict Frog
• ##### Derelict Frog

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### #1 Posted 11 October 2009 - 10:58 AM

A friend and I decided to calculate how tall the Rotterdam tower was. We nerded out:

1.) Take a helicopter with both of you inside.

2.) Fly to the highest possible height in the game.

3.) The Rotterdam Tower is about this height give or take 10m (Assumption: as we jumped out over water, this cancels out the effect of the spire we cannot reach in the heli; but the added fall into water is a few metres farther than a fall onto the ground).

4.) I jump out of the helicopter and the moment I exit I start the stopwatch.

5.) When I hit the water I stop the stopwatch.

6.) The time read 9.552 seconds - which is about 10 seconds to 1 significant figure (given the gross inaccuracies of this experiment).

7.) We could just calculate the distance here, but to be more accurate we must factor in terminal velocity (which is around 120mph or 54m/s).

8.) Thus, when at terminal velocity (54m/s) we can use v=u+a(t1) to work out what t is (v is final speed, u is initial speed [0 as I just jumped out of the heli], a is acceleration (under gravity .'. approximately 9.8 m/s^2).

9.) (t1)=5.5s

10.) .'. the distance fallen in the first 5.5 seconds is (s1)=ut+0.5a(t1)^2 (s is distance travelled/fallen)

11.) (s1)=148m

12.) (t2)=10-(t1) .'. (t2)=4.5s

13.) Now acceleration is 0 as we are at terminal velocity (constant speed of 54m/s)

14.) (s2)=ut+0.5at^2 .'. (s2)=243m

15.) .'. total distance fallen = 243 + 148 = 391m which is 390m to 2 significant figures.

The actual height of the Empire state building to its roof is around 380m. The height to the spire (which we tried to reach but could not factor in properly) is around 450m. So, since my height is out from the actual roof-height by less than 3% (within a 5% significance level) I can say R* did a good job in modelling the Rotterdam Tower on the Empire State Building.

Man - I have a some wasted hours

Edited by Derelict Frog, 11 October 2009 - 01:30 PM.

Mr. Someguy
• ##### Mr. Someguy

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### #2 Posted 11 October 2009 - 11:04 AM

That's actually pretty cool.

Good work!

ikt
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### #3 Posted 11 October 2009 - 11:08 AM

Nice work there.

DJSmurf2009
• ##### DJSmurf2009

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### #4 Posted 11 October 2009 - 11:13 AM

Im guessing some people have A LOT of time on thier hands lol

Good job though mate, pretty interesting!

Lubas
• ##### Lubas

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### #5 Posted 11 October 2009 - 01:18 PM

good job mate, Well done

skateordie985
• ##### skateordie985

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### #6 Posted 11 October 2009 - 04:11 PM

umm...

GTA_getaway_driver
• ##### GTA_getaway_driver

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### #7 Posted 11 October 2009 - 04:22 PM

What kind of genius plays GTA?
And why did you plan do do this?
And good job.

BenMc20
• ##### BenMc20

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### #8 Posted 11 October 2009 - 04:47 PM

If your working outs right I think it speaks for how good the physics are if R* actully took into account things like terminal velocity, I know the games realistic but incorporating the unseen rules of physics to that degree is impressive.

ioN
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### #9 Posted 11 October 2009 - 07:19 PM

Or you could just do it on single player(don't jump off anything higher then the tower or it wont work). Be sure to do it in a chopper or you'll hit the walls on the way down. Then after that when you respawn check your longest free fall distance. It should be around 382 or so.

But your way works as well. But takes a bit longer.

Magic_Al
• ##### Magic_Al

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### #10 Posted 11 October 2009 - 07:57 PM

In a game whose fun depends on vehicles flying through the air every which way, are we sure about 100% realistic gravity and mass?

Haven't modders figured out the model scale yet?

Derelict Frog
• ##### Derelict Frog

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### #11 Posted 11 October 2009 - 10:03 PM

 QUOTE (ioN @ Oct 11 2009, 19:19) Or you could just do it on single player(don't jump off anything higher then the tower or it wont work). Be sure to do it in a chopper or you'll hit the walls on the way down. Then after that when you respawn check your longest free fall distance. It should be around 382 or so.But your way works as well. But takes a bit longer.

Damn - that would've been quicker

spaceeinstein
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### #12 Posted 12 October 2009 - 01:31 AM

The height from the ground to the accessible roof is 320 m. To the highest flat spot (below the spire) is 376 m. I haven't tried the spire yet. Your calculations are right so your data are off.

Edited by spaceeinstein, 12 October 2009 - 01:35 AM.

staurday777
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### #13 Posted 14 October 2009 - 07:59 AM

 QUOTE (ioN @ Oct 11 2009, 19:19) Or you could just do it on single player(don't jump off anything higher then the tower or it wont work). Be sure to do it in a chopper or you'll hit the walls on the way down. Then after that when you respawn check your longest free fall distance. It should be around 382 or so.But your way works as well. But takes a bit longer.

lol he just got owned... its funny because he wasted his time

reform
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### #14 Posted 14 October 2009 - 10:16 PM

Well it wasn't completly pointless. we now know that the in-game physics aren't 100% accurate.

For starters, I don't think there is an acceleration period before reaching terminal velocity while falling in GTAIV.

hendrix
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### #15 Posted 15 October 2009 - 08:43 AM

 QUOTE (reform @ Oct 14 2009, 22:16) For starters, I don't think there is an acceleration period before reaching terminal velocity while falling in GTAIV.

of course there is. If not, you'll be dead as you stumble, when you're drunk for example.

lloydo
• ##### lloydo

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### #16 Posted 15 October 2009 - 12:37 PM

That's some good Math there.

CJ4LIFE1294
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### #17 Posted 12 April 2013 - 03:12 PM

 QUOTE (Derelict Frog @ Sunday, Oct 11 2009, 10:58) A friend and I decided to calculate how tall the Rotterdam tower was. We nerded out:1.) Take a helicopter with both of you inside.2.) Fly to the highest possible height in the game.3.) The Rotterdam Tower is about this height give or take 10m (Assumption: as we jumped out over water, this cancels out the effect of the spire we cannot reach in the heli; but the added fall into water is a few metres farther than a fall onto the ground).4.) I jump out of the helicopter and the moment I exit I start the stopwatch.5.) When I hit the water I stop the stopwatch.6.) The time read 9.552 seconds - which is about 10 seconds to 1 significant figure (given the gross inaccuracies of this experiment).7.) We could just calculate the distance here, but to be more accurate we must factor in terminal velocity (which is around 120mph or 54m/s).8.) Thus, when at terminal velocity (54m/s) we can use v=u+a(t1) to work out what t is (v is final speed, u is initial speed [0 as I just jumped out of the heli], a is acceleration (under gravity .'. approximately 9.8 m/s^2).9.) (t1)=5.5s10.) .'. the distance fallen in the first 5.5 seconds is (s1)=ut+0.5a(t1)^2 (s is distance travelled/fallen)11.) (s1)=148m12.) (t2)=10-(t1) .'. (t2)=4.5s13.) Now acceleration is 0 as we are at terminal velocity (constant speed of 54m/s)14.) (s2)=ut+0.5at^2 .'. (s2)=243m15.) .'. total distance fallen = 243 + 148 = 391m which is 390m to 2 significant figures.The actual height of the Empire state building to its roof is around 380m. The height to the spire (which we tried to reach but could not factor in properly) is around 450m. So, since my height is out from the actual roof-height by less than 3% (within a 5% significance level) I can say R* did a good job in modelling the Rotterdam Tower on the Empire State Building. Man - I have a some wasted hours

M Y B R A I N C A N T T A K E I T

TheDemonOfDeathValley
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### #18 Posted 13 April 2013 - 05:14 AM

Awesome.

I definitely think it should've been done with the 'longest freefall' technique, though.

SunflowerSeed
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### #19 Posted 14 April 2013 - 09:25 AM

 QUOTE (reform @ Wednesday, Oct 14 2009, 22:16) Well it wasn't completly pointless. we now know that the in-game physics aren't 100% accurate. For starters, I don't think there is an acceleration period before reaching terminal velocity while falling in GTAIV.

fite me 1v1 ill wreck you kid yolo

GKP
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### #20 Posted 14 April 2013 - 01:58 PM

Derelict - come post on the V forums...we will need someone who is mathematically persuaded to work out mountain heights..focal angles etc soon.

Interesting that R* use a realistic 9.81m 2 acceleration figure for gravity. I would of thought it would be of less strength. The cars in IV can be quite 'floaty' in the air and have more hang time than I would of expected irl.

EDIT - Right a 4 year old thread. Who bumped this ? and why lol

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